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Edit: /usr/lib64/python3.6/lib-dynload/_crypt.cpython-36m-x86_64-linux-gnu.so (7736B)
ELF> @@8 @x x ` ` `  x x x  888$$X X X StdX X X Ptd ,,QtdRtd` ` ` GNULZjM/Qs @   |CEqXsDl  , F"    ` __gmon_start___ITM_deregisterTMCloneTable_ITM_registerTMCloneTable__cxa_finalizelibcrypto.so.1.1libcrypt.so.1libpython3.6m.so.1.0libpthread.so.0libc.so.6PyArg_ParseTuplePy_BuildValue__stack_chk_failPyInit__cryptPyModule_Create2_edata__bss_start_endGLIBC_2.4GLIBC_2.2.5XCRYPT_2.00ii  ui f`] ` h p p `  h x     `            HH HtH5J %K hhhhhh% D% D% D% D% D% DH= H H9tH Ht H= H5 H)HHH?HHtHu HtfD=m u+UH=R Ht H= )dE ]wH(HH5dH%(HD$1HT$HL$1t Ht$H|$H=_H1HL$dH3 %(uH(ff.fH=0 HHss:crypts_crypt;,H(pHzRx $hpFJ w?:*3$"D`\sH0e A xGNUp Uft 0 x ` h o` +    oo0ooox `pcrypt($module, word, salt, /) -- Hash a *word* with the given *salt* and return the hashed password. *word* will usually be a user's password. *salt* (either a random 2 or 16 character string, possibly prefixed with $digit$ to indicate the method) will be used to perturb the encryption algorithm and produce distinct results for a given *word*.   ` GA$3a10 _crypt.cpython-36m-x86_64-linux-gnu.so-3.6.8-78.el8_10.alma.1.x86_64.debug2j7zXZִF!t/7]?Eh=ڊ2N.D$nX$MSNiƢbLaJ,14"PpᲺjLw" xktΓrC-9[w*fv9932f%mIuə/1JC3&5E9C%IdxC=lH{j>D#J1P(Pt/?89E52N<T cvEty|}QfyLIPSCDId~#S=-JRUy:JfƤ( >h&0d{^>re >'_J-u R3r][2QuJZْ-)sƥDN G~,-K{$xj璅Sɥb>ͅDjZo<80?V؂VP͗hm#,]|lyk$xd-_v=%֕>SP`e%Mvc_x jr;Je@Aw7/ϹB7= Xr6x)&udNi`QuC$y8<.zGd -6"ǹ]7-oY($_S`d*l5? 8Z*H^6/ Bx$+#*[bWB'igYZ.shstrtab.note.gnu.build-id.gnu.hash.dynsym.dynstr.gnu.version.gnu.version_r.rela.dyn.rela.plt.init.plt.sec.text.fini.rodata.eh_frame_hdr.eh_frame.note.gnu.property.init_array.fini_array.data.rel.ro.dynamic.got.data.bss.gnu.build.attributes.gnu_debuglink.gnu_debugdata 88$o``4( P0+8oEo00PT ^Bh00cPPpn`w  U}x x 2  , X X ` ` h h p p x x  h   `$ ,P|T(